simplify
(4t^2 - 1) ÷ (2t - 1)
(2t + 1)(2t - 1) ÷ (2t - 1)
= (2t + 1)
[(2t-1)(2t+1)]/(2t-1)
2t+1 when t <> 1/2
You must put the domain exception in or the answer is NOT correct.
Because at t=1/2 is defined for f(x) = 2t+1 but not defined in the original problem
f(x) = (4t^2 - 1) ÷ (2t - 1)
2t+1
(4t^2 - 1) / (2t - 1)
= (2t-1)(2t+1) / (2t-1)
= 2t+1
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Verified answer
(4t^2 - 1) ÷ (2t - 1)
(2t + 1)(2t - 1) ÷ (2t - 1)
= (2t + 1)
[(2t-1)(2t+1)]/(2t-1)
2t+1 when t <> 1/2
You must put the domain exception in or the answer is NOT correct.
Because at t=1/2 is defined for f(x) = 2t+1 but not defined in the original problem
f(x) = (4t^2 - 1) ÷ (2t - 1)
2t+1
(4t^2 - 1) / (2t - 1)
= (2t-1)(2t+1) / (2t-1)
= 2t+1