3 sin²x + 2 sin x = 5?
3 sin²x + 2 sin x = 5
Use factoring, the quadratic formula, or identities to solve the equation. Find all solutions in the interval [0, 2pi)
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3 sin²x + 2 sin x = 5
Use factoring, the quadratic formula, or identities to solve the equation. Find all solutions in the interval [0, 2pi)
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Verified answer
3sin^2 x + 2sin(x) - 5 = 0
(3sin(x) + 5)*(sin(x) - 1 ) =0
If 3 sin(x) + 5 = 0 then
3 * sin(x) = 5
sin(x) = 5/3 which is impossible because the sine of x cannot exceed 1
Sin(x) - 1 = 0
sin(x) = 1
That happens only when x = pi/2 when x is between 0 and 2 pi