2x(x-5)(x+6)(x-1) is the answer but not sure how to get there...
THanks
Factor out the common factor:
2x (x^3 - 31x + 30)
Look at the graph of y = x^3 - 31x + 30 or use the rational roots theorem to find the zeros at x = -6, x = 1 and x = 5.
Use the factor theorem to convert these zeros into factors:
(x + 6) (x - 5) (x - 1)
So altogether the factorization is:
2x (x + 6) (x - 5) (x - 1)
2x^4 - 62x² + 60x
x(2x^3 - 62x + 60)
2x(x-5)(x+6)(x-1)
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Verified answer
Factor out the common factor:
2x (x^3 - 31x + 30)
Look at the graph of y = x^3 - 31x + 30 or use the rational roots theorem to find the zeros at x = -6, x = 1 and x = 5.
Use the factor theorem to convert these zeros into factors:
(x + 6) (x - 5) (x - 1)
So altogether the factorization is:
2x (x + 6) (x - 5) (x - 1)
2x^4 - 62x² + 60x
x(2x^3 - 62x + 60)
2x(x-5)(x+6)(x-1)