Verified answer

2(x + 3) >= 20

x + 3 >= 10

x >= 7

Divide both sides by 2, since 2 is positive, the direction of the inequality is unchanged

[2(x+3)]/2 >= 20/2

x+3 >= 10

Subtract 3 from both sides

x + 3 -3 = x >= 10 - 3 = 7

x >= 7

2(x+3)≥20

2x + 6 ≥ 20

2x + 6 - 6 ≥ 20 - 6

2x / 2 ≥ 14 / 2

x ≥ 7

to prove the answer is right (we had to do this):

2(7 + 3) ≥ 20

2(10) ≥ 20

20 ≥ 20

2(x+3) ≥ 20

2x + 6 ≥ 20

-6 -6

2x ≥ 14

÷2 ÷2

x ≥ 7

2(x+3)>= 20

2x+6>= 20

2x+6-6>=20-6

2x>=14

x>=7

2(x+3)≥20

2x+6≥20

2x≥14

x≥7

2(x+3) >= 20

Divide each side by 2

x + 3 >= 10

Subtract 3 from each side

x >= 7