As you might have concluded from other's posts, the Pythagorean Theorem is pretty important to learn.
It even in works in higher dimensions, too. For example, if you the diagonal of a rectangular cuboid with sides 3, 4, and 5, you can still use the Pythagorean Theorem:
Yes. Remember the right triangles sides a, b, and the hypoteneuse c, and that a squared + b squared = c squared. If c is 4 X the square root of 5, and you square that (that is, c squared) you get 16 times 5, or 80, and 80 = 4 squared plus 8 squared.
True, as can easily be seen by applying Pythagoras. Taking squares of the sides, we have 16, 64, and 80, so Pythagoras applies and the triangle is a right triangle.
In a stunning anglr triangle ABC, if AC is the longest area (hypo) then AB^2+BC^2 = AC^2 4^2+8^2 = (8.9)^2 sixteen+sixty 4 = (8.9)^2 80 = (8.9)^2 (8.944)^2= (8.9)^2 however the size of AC given is 8.9 cm & as in keeping with calculation it is going to be 8.944 cm. Approximating it to one digit after decimal, the two will become comparable. as a result, given triangle is a stunning perspective triangle.
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Verified answer
Yes, it forms a right triangle. Use the pythagorean theorem.
4 squared plus 8 squared = Four root 5 squared.
16 + 64 = (4root5)^2
16 + 64 = 80
Yup.
As you might have concluded from other's posts, the Pythagorean Theorem is pretty important to learn.
It even in works in higher dimensions, too. For example, if you the diagonal of a rectangular cuboid with sides 3, 4, and 5, you can still use the Pythagorean Theorem:
3^2 + 4^2 + 5^2 = d^2
9 + 16 + 25 = d^2
50 = d^2
5 sqrt(2) = d
Yes. Remember the right triangles sides a, b, and the hypoteneuse c, and that a squared + b squared = c squared. If c is 4 X the square root of 5, and you square that (that is, c squared) you get 16 times 5, or 80, and 80 = 4 squared plus 8 squared.
True, as can easily be seen by applying Pythagoras. Taking squares of the sides, we have 16, 64, and 80, so Pythagoras applies and the triangle is a right triangle.
In a stunning anglr triangle ABC, if AC is the longest area (hypo) then AB^2+BC^2 = AC^2 4^2+8^2 = (8.9)^2 sixteen+sixty 4 = (8.9)^2 80 = (8.9)^2 (8.944)^2= (8.9)^2 however the size of AC given is 8.9 cm & as in keeping with calculation it is going to be 8.944 cm. Approximating it to one digit after decimal, the two will become comparable. as a result, given triangle is a stunning perspective triangle.
a^2 + b^2 = c^2
4^2 + 8^2 = (4sqrt(5))^2
16 + 64 = (sqrt(80))^2
80 = 80
True
the legs are 4cm and 8cm, the hypothenuse is 4sqrt(5)cm
O GOD geometry?? math is my worst nightmare. i dont kno!