Ola FERNANDO
regra
i^(4k+0) = 1
i^(4k+1) = i
i^(4k+2) = -1
i^(4k+3) = -i
1) i² = -1, i¹³ = i, i²¹ = i
2)
6*(cos 7pi/4 + i sen 7pi/4) = 6*(√2/2 - i √2/2) = 3√2*(1 - i)
pronto
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Answers & Comments
Ola FERNANDO
regra
i^(4k+0) = 1
i^(4k+1) = i
i^(4k+2) = -1
i^(4k+3) = -i
1) i² = -1, i¹³ = i, i²¹ = i
2)
6*(cos 7pi/4 + i sen 7pi/4) = 6*(√2/2 - i √2/2) = 3√2*(1 - i)
pronto